This post has been a bit
A few multiple choice questions on work energy and power were discussed in the last post. Here are a few more multiple choice questions in this section:
(a) decrease of 4 J
(b) increase of 4 J
(c) decrease of 8 J
(d) increase of 4 J
(e) decrease of 9 J
The initial kinetic energy of the particle = p2/2m = 62/(2×2) = 9 J.
The force F of 2 N actng on the particle for the time t equal to 2 s imparts a momentum Ft equal to 4 kg ms–1 along the negative direction. Since the initial momentum of the particle is along the positive x-direction, the resultant momentum is 6 – 4 = 2 kg ms–1.
Therefore, the final kinetic energy of the particle = 12/(2×2) = 1 J.
The change in the kinetic energy of the particle is 1 – 9 = – 8 J
The kinetic energy of the particle is thus decreased by 8 J.
(2) An elevator motor creates a tension of 5000 N in a hoisting cable and reels it at 0.8 ms–1. If the efficiency of the elevator system is 80%, the power input to the motor is
(a) 2 kW
(b) 4 kW
(c) 6 kW
(e) 10 kW
The power output (Pout) of the system is Fv = 5000×0.8 = 4000 W.
If the power input is Pin we have
efficiency h = Pout/ Pin
Therefore, 80/100 = 4000/Pin so that Pin = 5000 W = 5 kW.
(3) A liquid of density ρ is being continuously pumped through a pipe of area of cross section a. If the speed of the liquid through the pipe is v, the time rate at which kinetic energy is being imparted to the liquid is
The mass of liquid flowing per second is avρ. Therefore, the time rate at which kinetic energy is imparted to the liquid is ½ (avρ)v2 = av3ρ/2
The above questions will be beneficial for AP Physics B as well as C. The following questions are for AP Physics C aspirants:
(4) A machine
Since the power is the product of force and velocity we have
Fv = K where K is a constant.
If m is the mas and v is the velocity of the object, the above equation can be written as
M(dv/dt)v = K so that vdv = (K/m)dt
Intrgrating, v2/2 = (K/m)t
Therefore v α t1/2.
If ‘s’ is the displacement, v = ds/dt so that (ds/dt) α t1/2.
Integrating, s α t3/2 [Option (d)].
(5) The velocity v, momentum p and the kinetic energy E of a particle are related as
(a) p = dv/dE
(b) p = dE/dv
(c) p = (dE/dv)1/2
(d) p = d2E/dv2
(e) p = (dE/dv)2
If the mass of the particle is m we have E = ½ mv2
Differentiating, dE/dv = mv = p.